Post by Joshua Alvarez on Apr 14, 2016 0:27:15 GMT
Abstract
The common perception of the earth's curvature as 8 inches per mile squared comes from the archaic approximations of the 1800's. A fresh look at the earth's rate of curvature is necessary to perform accurate predictions concerning the concave earth. This submission hypothesizes that the correct rate of curvature in metric is 7.85 cm per km squared. Possible refutations of this hypothesis include the direct mechanical measuring of earth's curvature, a measured trip across the diameter of the earth, and a measured trip across the inside circumference of the earth. This new figure is virtually equivalent to 8 inches per mile squared, which vindicates the archaic approximations of the 1800's.
Introduction
Most people today do not know the rate of curvature of the concave earth in metric. Rather, ever since The Cellular Cosmogony was published, and since the birth of the flat earth movement, most people know the curvature of the earth as 8 inches per mile squared. Yet no attempt has been made as of yet to recalculate precisely with accurate calculators the correct rate of curvature in metric since the 1800's. Most people simply parrot the "8 inches per mile" line without knowing themselves why this is so or how to verify it. The following is my personal attempt to provide a fresh look at the issue with a precise online calculator.
Hypothesis
I propose (under the inspiration of the original Koreshians) that the earth's inner surface is a perfect sphere (with reference to the oceans) precisely the same size as the hypothetical outer circumference of the popular convex spinning ball. This size (according to Universe Today) is 40,041 km. The amount of curvature can be calculated as follows (with the help of WEB 2.0 CALC):
1. (Division into Tau) 40,041 km / 6.283185307 = 6372.7230765247267917 km.
Explanation: Since Tau is defined as the ratio of a Circumference to its Radius, division of the proposed circumference of the earth into Tau results in the proposed radius of it.
2. (Squaring with the Pythagorean Theorem) (6372.7230765247267917 km)2 + (1)2 = 40611600.4100707788443994087 km.
Explanation: Since the vertical radius of the earth and a horizontal line distance of 1 km form a right angle, another line connecting the two can be made (i.e. a hypotenuse). This new line is slightly longer than the radius. The extra length achieved with the previous 1 km of ground distance is the approximate distance of upward curvature. Since a2 + b2 = c2, so too does the radius squared plus the distance squared equal the hypotenuse (radius + amount of curvature) squared.
3. (Square Rooting the Squared Hypotenuse) √40611600.4100707788443994087 km = 6372.7231549841217658700534 km.
Explanation: Square rooting the squared hypotenuse gives us the hypotenuse.
4. (Subtracting the Radius from the Hypotenuse) 6372.7231549841217658700534 - 6372.7230765247267917 = 0.0000784593949741700534 km.
Explanation: Subtracting the radius from the hypotenuse (radius + amount of curvature) leaves only the amount of curvature in 1 km.
5. (Conversion from km to cm) 0.0000784593949741700534 km * 100000 = 7.84593949741700534 cm.
Explanation: A simple conversion from km to cm reveals the approximate curvature of the earth is 7.85 cm per km squared.
With this rate of curvature, a simple formula can be used to calculate the approximate upward curvature of the earth (mentioned above): 7.85 cm * x km2. x is the ground distance in km. For example, the curvature in 1 km is 7.85 cm. The curvature in 2 km is 31.4 cm. The curvature in 3 km is 70.65 cm, and so on. Also, the predicted diameter in the concave earth would be about 12,745 km.
Possible Refutation
There are three possible ways in which my hypothesis could be refuted. The first way is to mechanically measure the earth's curvature and discover a measured value significantly off from my hypothesized amount of 7.85 cm per km squared. The second way is to travel in a straight line in the earth across the diameter and discover the proposed diameter of 12,745 km to be very off. The third way is to travel across the inner circumference of the earth and discover the proposed circumference of 40,041 km to be significantly off.
Summary
My hypothesis is that the rate of the earth's curvature is 7.85 centimeters per kilometer squared. I also propose that the earth's inner diameter is 12,745 kilometers across. Experiments to consider performing are building a mechanical apparatus to compare it with the earth's curvature, traveling across the diameter of the earth, and traveling across the earth's inner circumference.
The common perception of the earth's curvature as 8 inches per mile squared comes from the archaic approximations of the 1800's. A fresh look at the earth's rate of curvature is necessary to perform accurate predictions concerning the concave earth. This submission hypothesizes that the correct rate of curvature in metric is 7.85 cm per km squared. Possible refutations of this hypothesis include the direct mechanical measuring of earth's curvature, a measured trip across the diameter of the earth, and a measured trip across the inside circumference of the earth. This new figure is virtually equivalent to 8 inches per mile squared, which vindicates the archaic approximations of the 1800's.
Introduction
Most people today do not know the rate of curvature of the concave earth in metric. Rather, ever since The Cellular Cosmogony was published, and since the birth of the flat earth movement, most people know the curvature of the earth as 8 inches per mile squared. Yet no attempt has been made as of yet to recalculate precisely with accurate calculators the correct rate of curvature in metric since the 1800's. Most people simply parrot the "8 inches per mile" line without knowing themselves why this is so or how to verify it. The following is my personal attempt to provide a fresh look at the issue with a precise online calculator.
Hypothesis
I propose (under the inspiration of the original Koreshians) that the earth's inner surface is a perfect sphere (with reference to the oceans) precisely the same size as the hypothetical outer circumference of the popular convex spinning ball. This size (according to Universe Today) is 40,041 km. The amount of curvature can be calculated as follows (with the help of WEB 2.0 CALC):
1. (Division into Tau) 40,041 km / 6.283185307 = 6372.7230765247267917 km.
Explanation: Since Tau is defined as the ratio of a Circumference to its Radius, division of the proposed circumference of the earth into Tau results in the proposed radius of it.
2. (Squaring with the Pythagorean Theorem) (6372.7230765247267917 km)2 + (1)2 = 40611600.4100707788443994087 km.
Explanation: Since the vertical radius of the earth and a horizontal line distance of 1 km form a right angle, another line connecting the two can be made (i.e. a hypotenuse). This new line is slightly longer than the radius. The extra length achieved with the previous 1 km of ground distance is the approximate distance of upward curvature. Since a2 + b2 = c2, so too does the radius squared plus the distance squared equal the hypotenuse (radius + amount of curvature) squared.
3. (Square Rooting the Squared Hypotenuse) √40611600.4100707788443994087 km = 6372.7231549841217658700534 km.
Explanation: Square rooting the squared hypotenuse gives us the hypotenuse.
4. (Subtracting the Radius from the Hypotenuse) 6372.7231549841217658700534 - 6372.7230765247267917 = 0.0000784593949741700534 km.
Explanation: Subtracting the radius from the hypotenuse (radius + amount of curvature) leaves only the amount of curvature in 1 km.
5. (Conversion from km to cm) 0.0000784593949741700534 km * 100000 = 7.84593949741700534 cm.
Explanation: A simple conversion from km to cm reveals the approximate curvature of the earth is 7.85 cm per km squared.
With this rate of curvature, a simple formula can be used to calculate the approximate upward curvature of the earth (mentioned above): 7.85 cm * x km2. x is the ground distance in km. For example, the curvature in 1 km is 7.85 cm. The curvature in 2 km is 31.4 cm. The curvature in 3 km is 70.65 cm, and so on. Also, the predicted diameter in the concave earth would be about 12,745 km.
Possible Refutation
There are three possible ways in which my hypothesis could be refuted. The first way is to mechanically measure the earth's curvature and discover a measured value significantly off from my hypothesized amount of 7.85 cm per km squared. The second way is to travel in a straight line in the earth across the diameter and discover the proposed diameter of 12,745 km to be very off. The third way is to travel across the inner circumference of the earth and discover the proposed circumference of 40,041 km to be significantly off.
Summary
My hypothesis is that the rate of the earth's curvature is 7.85 centimeters per kilometer squared. I also propose that the earth's inner diameter is 12,745 kilometers across. Experiments to consider performing are building a mechanical apparatus to compare it with the earth's curvature, traveling across the diameter of the earth, and traveling across the earth's inner circumference.